That will obviously depend on the specific problem. If you have an equation with a variable under a square root sign, it often helps to square both sides of the equation.
If you move that 46x over the equals, and if you square both sides, you can get rid of that square root, and do the equation normally. do the math
46x by 87y -------------- √ 90 Tips: If you move that 46x over the equals, and if you square both sides, you can get rid of that square root, and do the equation normally.
9x2 = 81 x2 = 9 <-- Divide both sides by nine x = 3 <-- Square root both sides All in all this is NOT a difficult equation.
(n+4)2 = 36 This is your equation. To solve for it square root of both sides then minus the 4 from both sides and you find your "n" n+4= 6 n=2 Your variable equals 2
Take the square root of both sides of the equation
That will obviously depend on the specific problem. If you have an equation with a variable under a square root sign, it often helps to square both sides of the equation.
facctor the problem and atke the square root of both sides
If you move that 46x over the equals, and if you square both sides, you can get rid of that square root, and do the equation normally. do the math
Since the area equals pi times the square of the radius, the radius must be the square root of (the area divided by pi). I got that by dividing both sides of the equation by pi then taking the square root of both sides.
A = pi * r2, so by dividing both sides of the equation by pi then taking the square root of both sides, you get... r = (A/pi)½ (r equals the square root of the quotient of A divided by pi.)
take the square root of both sides.
y2 = 169 Square root both sides: y = 13
x2 = 81 Square root both sides:- x = +/- 9
46x by 87y -------------- √ 90 Tips: If you move that 46x over the equals, and if you square both sides, you can get rid of that square root, and do the equation normally.
The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
The area of a circle is given by the equation A=πr2.To solve for r, divide both sides by π, then take the square root of both sides of the equation.This leaves you with the equation r=sqrt(A/π)