Best Answer

9x2 = 81

x2 = 9 <-- Divide both sides by nine

x = 3 <-- Square root both sides

All in all this is NOT a difficult equation.

Q: How do you solve 9x squared x 81?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i

81 x 81 = 6561

x2 + 9x2 = 10x2

812 = 81 x 81 = 6,561

9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0

Related questions

If you mean: x squared+9x+14 = 0 then by using the quadratic equation formula x = -2 or x = -7

3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3

x2-9x can be factored by taking x out of each term x(x-9)

9x+27 = -81 9x = -81-27 9x = -108 x = -12

The answer? There is no "answer" There cannot be an answer because they are all different. In order to make calculations, the variables have to be the same. x squared, xy, y squared are the variables, and none of them match. Therefore your "answer" must look like this: 9x squared - 6xy + y squared - 81. Hope I Helped :D

32 + x = 259 + x = 25x = 25 - 9x = 16

9x - 20 = 61 Add 20 to both sides: 9x = 81 Divide both sides by 9: x = 9

- 8x2

Use the quadratic formula. x = -4.265564 or -0.234436

x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i

If: x square+9x-22 then it is (x-2)(x+11) when factored

-7