use the horizontal line text, a horizontal line intersects the graph of x3 -3 only once so it is one to one.
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y(y-3)(y+3)
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
Oh, dude, you're hitting me with some math lingo! So, when you say y 3, you're talking about y cubed. And when you say y3y3-y, you're basically asking for y cubed times y cubed minus y. So, technically, the answer is y to the 6th power minus y. Math can be fun, right?
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
x over x is one, so the problem would be 1-2-3/2=-5/3