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What is the LCM of 2x3 5y2 15xy2?
The LCM is 30x3y2.
How can you graph x2 - y2 equals 9?
Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.
How do you graph x2 plus y2 is less than or equal to 9?
It is the circular disc with centre at the origin and radius = 3 units.
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
How many solutions in y2?
y2 there will me many solutions
The curve with equation y2 equals x3 plus 3x2 is called the Tschirnhausen cubic?
y2=x3+3x2
How do you write median median line?
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
If 3 log x - 2 log y?
1
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
What is the GCF of 12u7 y2 x3 and 16u6 x8?
4u6x3
How do you solve X9 - Y6 equals X3 - Y2 Between each X and Y power is an exponent?
2x2-y2
How do you factor x3 plus y3?
(x2 - xy + y2)(x + y)
Can a graph be symmetrical about the x axis?
X = y2 =====
How do you determine the slope of a line on an graph?
Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.
What is 8x2 y x3 y2 5y?
Assumption 8x2 = eight times x squared Assumption: x3 is x to the third Assumption: y2 is y squared Answer 40 y to the fourth x to the fifth = 40 y4 x5
How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
When x3 and y2 what is the area of the triangle?
It is not possible to answer the question with the information given - particularly with the form in which it is given.
