12-6 = 6 feet
it depends on the material and circumference.
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
Use Pythagorean formula to solve: a2 + b2 = c2 , where a & b are the legs of the right triangle & c is the hypotenuse.so, a = 13m (height of the telephone pole) & b=9 m distance from the bottom of the pole.(13)2 + (9)2 = c2169 + 81 = c2c2 = 250c = SQRT(250)c = 15.81 m
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
You need more info, probably an angle of elevation or something like that. It may be 14ft tall.
sq root ( 144 + 36 ) = 13.416 feet (approx)
Using Pythagoras' theorem it is 6 times the sq rt of 5 which is about 13.416 feet to 3 decimal places
Using Pythagoras' theorem it is 18.385 feet rounded to 3 decimal places
A pole that is reaching
Using Pythagoras' theorem it is 21.932 feet in length rounded to 3 dp
Using Pythagoras' theorem it is sq rt of 218 which is about 14.765 ft rounded to 3 decimal places
17 foot
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
A string reaching from the top of a 14 foot poll that meets the ground 11 feet from the base of the pole is 17.03 ft long (assuming a straight, plumb pole and level ground.) If we look at the set up here, what we have is a right triangle. The ground meets the pole at 90 degrees. Therefore, we can use Pythagorean's theorem. The theorem tells us that, in a right triangle, the sum of the length of one leg (A) and the length of another (B) both having been squared will equal the length of the hypotenuse squared (C). Or. A2 + B2 = C2 We've got the lengths of A and B, let's put them in. 112 + 132 = C2 121 + 169 = C2 290 = C2 Now we take the square root of both sides. √290 = C C ~= 17.03
The height of the pole is 19.62ft
17.45 feet.
The foot of a reel is the part of the reel that attaches to the pole.