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How high is a tree that casts a 37 ft shadow at the same time a 4foot pole casts a 12 foot shadow?
It works out as 12 feet and 4 inches in height
How tall is a flag pole that casts an 18 ft shadow at the same time that a 6 ft man casts a 4 ft shadow?
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
How is a tree that casts a 28-ft shadow at the same time a 4-ft pole casts a shadow which is 9-ft long?
The height of the tree is in direct proportion to the pole and its shadow
A vertical pole 5 feet long casts a shadow of 2 feet if at the same time a nearby tree casts a shadow of 10 feet how tall is the tree?
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
What is the angle of elevation of the sun with the ground when the pole 7.6 meters casts a shadow 6.1 meters long?
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
