Since watt is a unit of power (how fast energy is transferred), you can do this with almost any amount of power - as little or as much as you want, depending on how fast you want to heat the water. The time it takes will depend on the initial temperature, the amount of water, and the power.
1 second
Roughly 4200 seconds, since the specific heat of water is around 4.2J/gK (ie it takes 4.2 joules to raise 1 gram by 1 Kelvin); 1 litre = 1000 grams, 1 Celcius (centigrade) = 1K, 1W = 1J/s.
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
97 because if you take your right hand and raise it in the air then put your left foot in the air it will reflect the sun in a 97 degree angle giving you your answer
195 joule..
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
The specific heat of a substance is the heat required to raise the temperature of one gram of the substance one degree centigrade.
A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.
"Calorie" comes to us from Latin "calor", meaning "warmth". A calorie is the energy required to raise the temperature of one gram of water by one degree centigrade.
4186 Joules per liter per deg C. Not clear if we are raising the temperature BY 135 deg or TO 135 deg. So the answer is 4186 x 100 x rise in temperature. (Joules).
1 second
Depends on how high you want to raise the gram of water ;).
This is the abbreviation for kilocalorie, the metric name for one thousand calories. thus, 1.0 kcal = 1,000 cal Kilocalorie is the amount of heat energy require to raise 1 kilo or 2.2 pounds of water one degree Celsius ( centigrade ). Similarly, a calorie is the amount of heat energy required to raise one cubic centimetre of water one degree.
Heat capacity is the amount of heat energy required to raise the temperature of a unit mass of a material one degree.
One calorie is needed to heat 1 gram of water 1 degree Celsius
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s