Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are 5! = 120 such numbers.
There are 90,000 such numbers.
8100
14
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
I believe there are 81. There are 9 after every multiple of 10, including 90.
the right answer is 10 cause there is o,1,2,3,4,5,6,7,8,9 so there 10 numbers in total which have 1 digit
There are 90 two-digit numbers... starting with 10 and ending with 99.
ten factorial = 10! = 3,628,800
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
72. (with the range of two digit numbers being from 10 to 99).
3
There are 9*10*9 = 810 such numbers.
There are 900 three digit numbers. (99 - 1000) (# of possible numbers in the first position = 9) (# of possible numbers in the second position = 10) (# of possible numbers in the third position = 10) 9 *10 *10 = 900
720 (10*9*8)