We have three cases:
1- Hundreds digit= Tens digit:
In every hundred 9 numbers are in this pattern:
110-112-113-114-115-116-117-118-119
and we have 9 hundreds, so in this case there are 81 numbers.
2- Hundreds digit= Units digit:
In every hundred 9 numbers are in this pattern:
101-121-131-141-151-161-171-181-191
and we have 9 hundreds, so in this case there are 81 numbers!
3- Tens digit= Units digit:
In every hundred 9 digits are in this pattern:
100-122-133-144-155-166-177-188-199,
and we have 9 hundreds, so in this case there are 81 numbers!
Total = 81 + 81 + 81 = 243
To find the number of 3-digit numbers with exactly 2 digits the same, we can break it down into cases. There are 9 choices for the repeated digit (1-9, excluding 0), 8 choices for the non-repeated digit, and 3 positions for the non-repeated digit in the number (hundreds, tens, or units place). Therefore, the total number of such numbers is 9 * 8 * 3 = 216.
There are 22680 numbers, excluding those with leading 0s.
There are 5460 five digit numbers with a digit sum of 22.
how many numbers exactly have 4 digits ? 8900, 8999, 9000, 9999
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
There are 60480 numbers.
1
Exactly 2: 243 of them.
Any pair of digits (not including 0), can be used to generate 14 four-digit numbers. If one of the digits is 0, only seven will start with a non-zero digit.
There are 22680 numbers, excluding those with leading 0s.
With 123 digits you can make 123 one-digit numbers.
There are 5460 five digit numbers with a digit sum of 22.
Zero; all six digit numbers have six digits. Dude.. i m asking 6 digit numbers, containing only 4 different digits..!! e.g.:123412.. with only 2 digits repeated..!! My guess is: 10*9*8*7*4*3 but I'm also guessing that is wrong- sorry!
how many numbers exactly have 4 digits ? 8900, 8999, 9000, 9999
27 three digit numbers from the digits 3, 5, 7 including repetitions.
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
7 two-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.