135: including 15 with two Os which are assumed to be indistinguishable.
If one of the Os is upper case and the other lower (so that Oct is different from oct), then the answer is 8*7*6 = 336.
Chat with our AI personalities
There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
Permutations of 10 letters taken 3 a time = 10 x 9 x 8 = 720
September has 9 letter, of which one appears 3 times. So the number of distinct permutations is 9!/3! = 120,960
because permutations are order specific, and because there are two d's "dad" counts as only one. so it is 6 (3P3)/2 (there are two d's) so the answer is 3 DAD ADD DDA
How many four-letter permutations can be formed from the letters in the word DECAGON?