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How many permutations exist of the letters a b c d taken four at a time?
Since you are using in the arrengement the all 4 letters, then there are 4! = 4*3*2*1 = 24 permutations.
How many 4 letter permutations can be formed from the word decagon?
5040
How many permutations can you get out of an eight word phrase?
There are 8! = 40320 permutations.
How many permutations are possible of the letters in the word Fresno?
There are 6! = 720 permutations.
How many different ways are there to to scramble to letters of the word mass if s needs to be the first letter?
The number of permutations of the letters MASS where S needs to be the first letter is the same as the number of permutations of the letters MAS, which is 3 factorial, or 6. SMAS SMSA SAMS SASM SSMA SSAM
How many 3 letter permutations of the word October?
There are 195 3-letter permutations.
How many permutations exist of the letters a b c d taken four at a time?
Since you are using in the arrengement the all 4 letters, then there are 4! = 4*3*2*1 = 24 permutations.
How many permutations of 5 letter can be made without any letters being repeated?
There are 7893600 permutations.
How many possible permutations using the word bite?
4! Four factorial. 4 * 3 * 2 = 24 permutations ------------------------
How many different 4 letter permutations are there for the letters in the word toolroom?
120 four letter permutations if you don't allow more than one 'o' in the four letterarrangement.209 four letter permutations if you allow two, three and all four 'o'.1.- Let set A = {t,l,r,m,}, and set B = {o,o,o,o}.2.- From set A, the number of 4 letter permutations is 4P4 = 24.3.- 3 letters from set A give 4P3 = 24, and one 'o' can take 4 different positions in theword. That gives us 24x4 = 96 four letter permutations.4.- In total, 24 + 96 = 120 different four letter permutations.5.- If the other three 'o' are allowed to play, then you have 2 letters from set A thatgive 4P2 = 12 permutations and two 'o' can take 4C2 = 6 position's, giving 12x6 = 72four letter permutations.6.- One letter from set A we have 4P1 = 4, each one can take 4 different positions, therest of the spaces taken by three 'o' gives 4x4 = 16 different permutations.7.- The four 'o' make only one permutation.8.- So now we get 72 + 16 + 1 = 89 more arrangements adding to a total of 89 + 120 = 209 different 4 letter arrangements made from the letters of the word toolroom.[ nCr = n!/((n-r)!∙r!); nPr = n!/(n-r)! ]
How many different three letter permutations can be from the letter in the word clipboard?
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
How many different 3 letter permutations can be formed from the letters in the word count?
There are 5*4*3 = 60 permutations.
How many permutations exist of the letters a b c d taken two at a time?
12
How many 4 letter permutations can be formed from the word decagon?
5040
How many permutations are possible of the word yard?
Imagine you have four empty buckets in which to put any of the four letters Y, A, R, D into. At first you have four letters that can be placed in any of the four empty buckets. Once you've placed a letter in a bucket you only have three letters and three empty buckets to choose from. And so on... So there are 4x3x2x1 = 24 permutations of the word YARD.
How many different four-letter permutations are there for the letters in the word toolroom?
loom, loot, molt, mool, moor, moot, mort, room, root, rotl, roto, tool, toom, toro
How many different 4 letter combinations can you make with 6 different letters?
6P4 = 6!/(6-4)! = 6 * 5 * 4 * 3 = 360 four letter permutations from 6 different letters.6C4 = 6!/[4!∙(6-4)!] = 15 four letter combinationsfrom 6 different letters.
