There are 6C3 = 20 such combinations.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are 8145060 combinations.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
900000
There are 6C3 = 20 such combinations.
There are 5,461,512 such combinations.
35
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are 8145060 combinations.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
The answer is 8C4 = 8*7*6*5/(4*3*2*1) = 70
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
4*3*2*1 = 24 different combinations.