Nine options, no repeats, three slots.The equation for this is as follows:
9!/(3!*(9-3)!)
9*8*7*6*5*4*3*2*1 / (3*2*1)*(6*5*4*3*2*1)
= 9*8*7 / 3*2*1
= 504 / 6
= 252 / 3
= 84
84 combinations.
There are 6C3 = 20 such combinations.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are 8145060 combinations.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
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how mant 5-number combinations are there with tnumbers 1 thru 35, please list them all?
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There are 6C3 = 20 such combinations.
There are 5,461,512 such combinations.
35
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
Including the null combination, there are 2^14 = 16384 combinations.
The number of combinations of 7 numbers from 10 is 10C7 = 10*9*8/(3*2*1) = 120
There are 8145060 combinations.