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To calculate the number of 4-digit numbers that can be formed using the digits 1, 3, 5, 7, and 9 without repetition, we use the permutation formula. Since there are 5 choices for the first digit, 4 choices for the second digit (as one digit has been used), 3 choices for the third digit, and 2 choices for the fourth digit, the total number of 4-digit numbers that can be formed is 5 x 4 x 3 x 2 = 120.
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How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many three digit numbers can be formed using 01234?
48 of them if digits may not be repeated. 100 if they can.
How many 2 digit numbers can be formed using the digits 1 3 5 7 9 and 0 if repeating is not allowed?
There are 25 such numbers.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3-digit numbers can be formed using the digits 0 2 3 without repetition?
# 230 # 203 # 320 # 302
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 3-digit numbers can be formed using the digits 1 2 3?
27
How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?
24 different numbers.
How many 3 digit numbers can be formed using even digits only?
More than one
How many three digit numbers can be formed using 01234?
48 of them if digits may not be repeated. 100 if they can.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 4-digit numbers can be formed by the digits 1 1 2 2 using the digits more than once?
6
How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many 9 digit numbers which are divisible by 4 can be formed by using the digits 1 to 5 if repetition of digits is not allowed?
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
How many 6-digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if digits can be repeated?
151200 numbers.
