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To calculate the number of 4-number combinations using the numbers 1, 2, 3, 4, and 5 without repetition, you can use the formula for permutations. Since order matters in a combination, you would use the formula for permutations, which is nPr = n! / (n - r)!. In this case, you would have 5 choices for the first number, 4 choices for the second number, 3 choices for the third number, and 2 choices for the fourth number. Therefore, the total number of 4-number combinations would be 5P4 = 5! / (5-4)! = 5 x 4 x 3 x 2 = 120 combinations.
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How many 5-digit numbers can be made only using the numbers 1 2 3 4 5 with out repeating a number twice example 12345 12354 12435?
120 5-digit numbers can be made with the numbers 12345.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many combinations can be formed using numbers 13579 in a 3 number sequence?
13579
How many 3 digit combinations are there in the numbers 1 to 9?
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
How many 3 digit numbers can be formed using 12345 with repition?
125
What are all the possible five digit combinations using the numbers 1-6?
7
How many combinations of 5 are there in 0 to 10 numbers?
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
How many 5-digit numbers can be made only using the numbers 1 2 3 4 5 with out repeating a number twice example 12345 12354 12435?
120 5-digit numbers can be made with the numbers 12345.
What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 4-number combinations using numbers 0-9?
9000
What are the combinations of 1 through 10 with out using them twice?
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many combinations can be formed using numbers 13579 in a 3 number sequence?
13579
How many 3 number combinations can you make using the numbers 1-45?
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
How many 3 digit combinations are there in the numbers 1 to 9?
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
How many possibly combinations are there using 9 numbers without using the same number in the order twice?
36324
