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To calculate the number of 4-number combinations using the numbers 1, 2, 3, 4, and 5 without repetition, you can use the formula for permutations. Since order matters in a combination, you would use the formula for permutations, which is nPr = n! / (n - r)!. In this case, you would have 5 choices for the first number, 4 choices for the second number, 3 choices for the third number, and 2 choices for the fourth number. Therefore, the total number of 4-number combinations would be 5P4 = 5! / (5-4)! = 5 x 4 x 3 x 2 = 120 combinations.
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How many 5-digit numbers can be made only using the numbers 1 2 3 4 5 with out repeating a number twice example 12345 12354 12435?
120 5-digit numbers can be made with the numbers 12345.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many combinations can be formed using numbers 13579 in a 3 number sequence?
13579
How many 3 digit combinations are there in the numbers 1 to 9?
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
How many 3 digit numbers can be formed using 12345 with repition?
125
