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Maths Problem Banks issue customers with 4 digit Pin Code numbers however the PIN codes have to have a pair of repeated digits 0889 6647 but not 3453 or 4444 how many codes are there?
the repeated digits can lie in any of 3 positions:XXYZ,YXXZ, or YZXXTherefore, the number of different possible repeated digit combinations is 10×3=30 (there are 10 different possible digits).There are then 9 values left that Y could be, after the X's have their values, and 8 values left that Z could be, to ensure no unintended repeated numbers.This gives (10×3)×9×8=2160. There are therefore 2160 possible codes.
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
How many possible 3 digit numbers can be made using the digits 604?
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
What is the greatest 5-digit even number with no digit repeated?
Proceed from left to right, using the largest possible digit in each position.
How many 3 digit numbers can be formed from the digits 12345 if the digits cannot be repeated?
1 set
How many different 4-digit codes are possible if the digits cannot be repeated?
If you include 0000, ten thousand unique four digit codes are possible.
How many 5 digit zip codes are possible if digits cannot be repeated?
100,000 - Every number from 00000 to 99999.
How many different 5-digit zip codes are possible if no digits are repeated?
10*9*8*7*6=30,240
How many three-digit area codes are possible if the first digit cannot be a 0?
There are 900 possible three-digit numbers not beginning with 0. (Note, however, that this question does not accurately describe the restrictions on numbers that can be used as area codes.)
How many different 5 digit zip codes are possible if digits are allowed to repeated?
As far as I can tell, all 5 digit numbers are potential zip codes, so there are 99999 + 1 potential zip codes, or 100,000. Many of these are not actually is use.
A combination lock on a suitcase has 5 wheels each labeled with digits 1 to 8 How many 5 digit combination lock codes are possible if no digit can be repeated?
6,720 combinations.
How many even 3-digit positive integers can be written using the digits 1 3 4 5 and6?
If a digit can be repeated there are 5 x 5 x 5 = 125 possible numbers If a digit cannot be repeated there are 5 x 4 x 3 = 60 possible numbers.
How many different 3-digit codes can be created if no digit can be repeated?
Any 3 from 10 in any order = 10 x 9 x 8 = 720It depends on what other restrictions you place on the numbers. For example, in North America (country code +1 = USA, Canada, etc.), area codes cannot have 0 or 1 as the first digit, and cannot have 9 as the second digit.
How many possible 3 digit area codes can be created without repeating a number?
The number of 3-digit numbers with no repeated digits is simply 10x9x8 = 720, if you allow, for example, 012 as a 3-digit number. There are 10 digits, any of which might be the first digit. The second digit can be any digit except the digit that was used for the first digit, leaving 9 possibilities. The third digit then has 8 possibilities, since it can't be the same as the first or second digit. The actual number of possible area codes will be lower, because there are additional restrictions on the number combinations for a valid area code. For example, in North America (USA, Canada, etc.), the first digit of an area code cannot be 0 or 1 and the middle digit cannot be 9.
Maths Problem Banks issue customers with 4 digit Pin Code numbers however the PIN codes have to have a pair of repeated digits 0889 6647 but not 3453 or 4444 how many codes are there?
the repeated digits can lie in any of 3 positions:XXYZ,YXXZ, or YZXXTherefore, the number of different possible repeated digit combinations is 10×3=30 (there are 10 different possible digits).There are then 9 values left that Y could be, after the X's have their values, and 8 values left that Z could be, to ensure no unintended repeated numbers.This gives (10×3)×9×8=2160. There are therefore 2160 possible codes.
How many different 4-digit codes are possible if the last digit has to be zero?
There can be 103 = 1000 codes.
How many two-digit numbers in base ten can be formed if the tens digit cannot be 0 and no digit can be repeated?
81
