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Assuming a 5 digit number cannot start with 0, ie it must be at least 10,000, then there are 96 possible numbers:

there are 4 choices for the first digit,

leaving a choice of 4 for the second digit for each of the choices for the first digit,

leaving a choice of 3 for the third digit for each of the choices for the first two digits,

leaving a choice of 2 for the fourth digit for each of the choices for the first three digits,

leaving a choice of 1 for the fifth (and final) digit for each of the choices for the first four digits,

Making a total number of choices 4 x 4 x 3 x 2 x 1 = 96

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Q: How many 5 digit numbers can be formed using 0 1 2 3 4 without repetition?
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