Best Answer

L = 156 cm

so L/2 = 156/2 = 78 cm

and so width = W = 36 cm more = 78+36 = 114 cm

Then perimeter = 2*(L+W) = 2*(156 + 114) cm = 2*270 cm = 540 cm

Q: How do you find the width and perimeter of a rectangle if the length is 156 cm and the width is 36 more than one half of the length?

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If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

The width is 10.5 cm.

If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2

Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.

Perimeter: Add the length of the four sides. Area: Multiply length x width.

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If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

you need length and width length multiply width = area length + length + width + width = perimeter

Length + length + width + width = perimeter. Length + width x 2 = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length

You divide the perimeter by the width and you get the lenght

Length = (Perimeter - twice width) / 2

by appying 2l+2w

length 18 width 7

Perimeter = 2*(L + W).