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From 8 numbers there are 28 possible 6 number combinations.

As you are selecting 6 numbers from 8 and the order of selection doesn't matter:

First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order.

However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways.

Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.

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Q: How many combinations are there if you have 8 numbers and there are 6 number combinations Just like in the maga millions lottery?
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