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To calculate the number of combinations in 123, we need to clarify what you mean by "123." If you are referring to the number "123," then there is only one combination. However, if you are referring to a set of three distinct items labeled 1, 2, and 3, then there are six possible combinations: {1, 2, 3}, {1, 3, 2}, {2, 1, 3}, {2, 3, 1}, {3, 1, 2}, and {3, 2, 1}.
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DevinOh, dude, you're hitting me with some math vibes. So, to calculate the number of combinations in 123, you'd use the formula n! / (r! * (n-r)!), where n is the total number of items and r is the number of items you're choosing. In this case, since you have 3 numbers in 123, there's only 1 way to arrange them. So, the number of combinations in 123 is just 1. Easy peasy, right?
Oh, what a happy little question! To find the number of combinations in 123, you can use a simple formula: n! / r!(n-r)!. In this case, n=3 and r=3, so it would be 3! / 3!(3-3)! which simplifies to 6 / (6*1), giving us 1 combination. Just remember, there are no mistakes, just happy little accidents in math!
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How many combinations of 123?
There is only 1 combination of the numbers 123. (order does not matter)There are 6 permutations of the numbers 123. (order does matter)1 2 31 3 22 1 32 3 13 1 23 2 1
Find three consecutive even integers that have a sum of 123?
Find three consecutive positive even integers whose sum is 123 , Answer
How many 3 digit combinations there 0-9?
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.
How many combinations the numbers one two and three using each digit only once can I get?
6 - 123, 132, 213, 231, 312, and 321.
How many combinations can you make with three numbers?
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
