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If using numbers 0 through 9 how many different 3 digit combinations can be made?
There are 10 possible digits that can be used: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. If you can only use each digit once, there are 10 choices for the first digit, 9 remaining choices for the second digit, and 8 remaining choices for the final digit - 10 x 9 x 8 = 720 combinations. If you can use each digit repeatedly, you have 10 choices for each digit - 10 x 10 x 10 = 1000 combinations.
What else can I help you with?
How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?
10!/3! = 604800 different combinations.
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many 3 digit combinations numbers one through nine?
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
How many different four digit combinations are there of the numbers zero through nine and using one number twice in the combination?
There are 360 of them.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
If using numbers 1 through 8 how many different 4 digit combinations can be made?
15
If using numbers 1 through 4 how many different 4 digit combinations can be made?
10,000
How many different combinations are possible multiplying 8 different 7 digit numbers?
56 combinations. :)
How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?
10!/3! = 604800 different combinations.
If using numbers 0 through 9 how many different 4 digit combinations can be made?
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many 3 digit combinations numbers one through nine?
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
How many different four digit combinations are there of the numbers zero through nine and using one number twice in the combination?
There are 360 of them.
What are all the number combinations for the numbers 1 through four?
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
What are the different combinations of three digit numbers using 0-9?
9
