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With 6 different letters, no repetition (like you have 6 different Scrabble tiles), and if order is important, then the proper statistical term is permutation, rather than combination, but many people refer to this type of application as a combination.
The permutation (no repetition) of n items taken rat a time is n!/(n-r)! with in this case n=6 and r=6. The exclamation mark is notation for factorial.
6! = 6 * 5 * 4 * 3 * 2 * 1. (6-6)! = 0! which is defined as 0! = 1
So we have 6 * 5 * 4 * 3 * 2 * 1 = 720 different possibilities.
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How could you find the number of different combinations of six letters in a computer password?
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.
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How could you find the number of different combinations of six letters in a computer password?
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I'm going to assume you mean combinations - the unique set of these letters in any order with no sequence repeated. With these letters, there are 60 possible combinations. To see the maths behind this, try typing "permutations of {c,c,c,p,p,k}" into wolfram alpha.
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How many total combinations are possible if you roll two six sided dice?
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How many combinations are possible for a six-digit lock?
Assuming each "digit" actually has 10 different states, there are one million combinations possible in a six-digit combination lock. However, many combination lock designs actually have fewer than 10 different states per "digit", resulting in far fewer actual combinations on such locks.
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