With 6 different letters, no repetition (like you have 6 different Scrabble tiles), and if order is important, then the proper statistical term is permutation, rather than combination, but many people refer to this type of application as a combination.
The permutation (no repetition) of n items taken rat a time is n!/(n-r)! with in this case n=6 and r=6. The exclamation mark is notation for factorial.
6! = 6 * 5 * 4 * 3 * 2 * 1. (6-6)! = 0! which is defined as 0! = 1
So we have 6 * 5 * 4 * 3 * 2 * 1 = 720 different possibilities.
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.
There are six possible combinations.
Assuming you mean exactly six letters - there are three English-language day names with six letters - Monday, Friday, Sunday.
Six.
Find the possible combinations of rolling a six with two dice: 1 + 5 = 6 5 + 1 = 6 2 + 4 = 6 4 + 2 = 6 3 + 3 = 6 3 + 3 = 6 Six in total. Find the number of possible combinations; Number of Sides on the Dice (6) to power of how many dice (2) = 36 Number of Times the Dice will sum to Six (6 times) -------------------------------------------------- Number of Possible outcomes This will give us 6 out of 36 rolls. Or reduced 1/6 rolls
Just 1.
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
266 x 10 = 3089157760.
3!(factorial) or six
I'm going to assume you mean combinations - the unique set of these letters in any order with no sequence repeated. With these letters, there are 60 possible combinations. To see the maths behind this, try typing "permutations of {c,c,c,p,p,k}" into wolfram alpha.
There are six possible combinations.
6X6=36
figure it out then tell me :)
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
Assuming each "digit" actually has 10 different states, there are one million combinations possible in a six-digit combination lock. However, many combination lock designs actually have fewer than 10 different states per "digit", resulting in far fewer actual combinations on such locks.
In a permutation problem such as this, there are six spaces, each of which could be one of two letters. This means there are sixty-four possible combinations. The two obvious combinations are aanwmn and ccpyop. Looking at those, the word is then canyon.