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There are 10 digits, 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.

Let's say that a three digits number has a form of xyz. There are only 9 possibilities for x (0 cannot be in the first place), 10 possibilities for y, and 10 possibilities for z. So there are 9 x 10 x 10 = 900 combinations.

However, there are only 9 digits from 1 to 9. So we have 9 possibilities for x, y, and z. Hence, there are 9 x 9 x 9 = 729 combinations.

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Q: How many combinations of three digits can be made with numbers 1 through 9?
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How many combinations can you make using numbers 1 through to 10 each with three different numbers?

1000


What are the possible different combinations of numbers in four digits?

If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.


How many 5 digit combos in 30 numbers?

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.


How many 3 digit numbers can be formed from the digits 0 through 9 in a set of three?

If the digits can be used more than once, then 900. If not, then 648.


How many 3 digit combinations there 0-9?

The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.

Related questions

How many combinations of three digits can be made from the numbers 123?

6


How many combinations of three digits can be made using thirty-two numbers?

32C3 = 4960


How many combinations of three digits can be made from numbers 1 - 3?

Six combinations: 123, 132, 213, 231, 312, 321


How many combinations of three digits can be made from the numbers 998?

Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.


What are the combinations of the numbers 5 6 7?

How many digits are in each combination ? ? -- If one, then there are three combinations: {5}, {6}, and {7) . -- If two, then there are three combinations: {5, 6}, (5, 7), and {6, 7}. -- If three, then there is only one combination: {5, 6, 7}


What are the combinations of 1 through 10 with out using them twice?

There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.


How many combinations of three digits can be made from the numbers 17 example 017 170 107 701 etc?

017, 071, 107, 170, 701, 710. 6 combinations


How many combinations can you make using numbers 1 through to 10 each with three different numbers?

1000


How many combination of three digits can be made from the number 0-9 that's larger than 15?

We notice that you said "combinations of three digits". You didn't say "3-digit numbers".There are (10 x 10 x 10) = 1000 combinations of three digits.The only combinations of 3 digits that form numbers less than 15 are 000, 001, 002, . . .012, 013, and 014. There are 15 of those.So the remaining (1000 - 15) = 985 are all larger than 15.


What are the possible different combinations of numbers in four digits?

If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.


How many combinations of three digits can be made from the numbers 1 to 10?

9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.


How many 5 digit combos in 30 numbers?

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.