346
67 i think maybe please answer it for me
A good arrengenent would be ,Three rows of three. Or 3*3=9 cubic units.
You would be adding volumes together; whatever configuration you put them would be irrelevant then. Assuming these are all 1" cubes, you would have first a long row of 8 (1"x1"x8" total) or a cube made of cubes (2"x2"x2" total) and they both come to 8 cubic inches.
Eight half inch cubes would fill a one inch cube.
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67 i think maybe please answer it for me
If you have 5 distinct cubes, the number of arrangements can be calculated using the factorial of the number of cubes. Thus, the total arrangements would be 5! (5 factorial), which equals 120. If the cubes are identical, there would be only 1 arrangement.
24 cubes would be it.
64
no
Eight 4 inch cubes are needed to build and 8 inch cube.
Well, isn't that just a delightful little stack of cubes you're imagining! To build a stack that is 3 cubes long, 2 cubes high, and 4 cubes deep, you would need a total of 24 cubes. Just imagine all the happy little details you could add to each cube as you stack them up!
2*2*2 = 8 cubes.
It would be very slow going and the walls would be very thick.
A good arrengenent would be ,Three rows of three. Or 3*3=9 cubic units.
Zero would be enough.
12