It should be obvious (it is, isn't it? am I expecting too much of today's educational system?) that the largest possible result of multiplying two two digit numbers is 99x99 = 9801, which has four digits, and the smallest possible result is 10x10 = 100, which has three digits.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
You had me until "product." The product of 4 digits can't be prime.
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
There are 15 of them.
The answer is 4. You get the answer by trying the example of the largest two digit number, 99. 99 x 99 = 9801. This has four digits, so you can't get more digits than this by multiplying two two digit numbers. * * * * * True, but you CAN have fewer: 10*10 = 100, which is only three digits! 1490 of the 8100 2 digit x 2 digit multiples have products of 3 digits, the rest have 4 digit products.
It is the unit's digit of the product of the unit's digits. For example, the units digit of 123456 * 4689 is simply the units digit of 6*9 = 54, which is 4.
from 3 digits (10x10) to 4 digits (99X99)
-21
There are three such numbers: 12, 24 and 36.
4 Give examples to support your answer please.
There are five such numbers: 11, 12, 15, 24 and 36.
If the question is about the product of all odd digits, the answer is 945. Otherwise the question does not make sense.