1 yd=3 ft. 16 yd= 48 ft. 294 - 48 = 246. 246 < 250, so the answer is NO.
draw it out. you have 2 sides of a triangle. use pythag theorm 26 squared- 10 squared 676-100=576 square root of 576 is 24. 24+24+10+10=68 you need 68 feet of fencing
The circumference of a rectangle is 2*(length+width), so 2*(18+23) = 2*(41) = 82 Therefore, 82 feet of fencing is required to enclose the garden.
i need help
They don't really translate like that. To enclose a 600 square foot area could take up to 1202 linear feet of fencing, but might work with less than a hundred, if the area was square.
4*33 = 132 feet
625 square feet.. the area would be a square rectangle with 25 feet of fencing on each side.
If the acreage is a square, you'll need 6,467 feet of fencing to enclose the area.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet..
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
That would probably be a 25x25 square with an area of 625 square feet.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
33 feet x 4 sides = 132 feet
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.