1 acre = 43,500 ft2vol = area * depth = 43,500*5 = 217,500 ft31 ft3 is approx. 7.48 gallons217,500 ft3 * (7.48 gal/ft3) = 1,626,900 gallons
1 acre = 43,560 square feet1 million acre-feet = (106) x (43,560) x (1) = 4.356 x 1010 cubic feet = 325,851,428,600 gallons (rounded)
how many gallons of water does a swimming pool 15 feet by 4 feet deep hold
1 acre = 43,560 square feet1 cubic foot = 1,728 cubic inches1 gallon = 231 cubic inchesVolume of the lake = (1.5 x 43,560) x (5) = 326,700 cubic feet = 2,443,885.7 gallons (rounded)
There's no way of telling. 18,000 gallons is roughly 2400 cubic feet. If the pool was six feet deep, the surface area would be 400 square feet. if the pool was eight feet deep, the surface area would be 300 square feet. It could be almost any configuration.
There are 27,154 gallons of water in one acre of land that is one inch deep.
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
The answer will depend on how deep the lake is!
27,154
Approximately 977,553 gallons of water.
Approximately 48,878,000 gallons.
It depends on the depth of the water. Assuming the water in one inch deep, there would be about 13,577 gallons of water in the half acre.
A 1000 acre lake that is 7 feet deep (uniformly) will have 7000 acre feet of water in it. An acre foot is an acre of water one foot deep, and the unit is used to measure reservoir water capacity. The conversion factor is that one acre foot equals about 325,851.5 gallons. The lake in question is holding 7000 times 325,851.5 gallons of water.
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
One acre-foot is 325,851.4 US gallons of water.
Approximately 8,146,286 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.