Oh, dude, let me break it down for you. So, you've got 8 numbers to choose from for each digit, and you're picking 4 digits in total. That means you have 8 choices for the first digit, 8 choices for the second digit, 8 choices for the third digit, and 8 choices for the fourth digit. Multiply all those together and you get... well, I'll let you do the math.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There are only 10 combinations. In each combination one of the 10 digits is left out.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
Yuo can make only one combination of 30 digits using 30 digits.
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.
128
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
654321-100000= 554321 combinations
There are only 10 combinations. In each combination one of the 10 digits is left out.
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
There are ten combinations: one each where one of the ten digits, 0-9, is excluded.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
Yuo can make only one combination of 30 digits using 30 digits.
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.