0
Still curious? Ask our experts.
Chat with our AI personalities
Vivi
Lao
CoachAdd your answer:
Earn +20 pts
At a party everyone shook hands with everybody else There were 66 handshakes How many people were at the party?
Each handshake involved 2 people so 12 guests: Guest A made 11 handshakes, B 10 having already been counted as an A-B handshake, C 9 etc for 2 ppl thr is 1 hand shakefor 3 thr is 3(1+2)for 4 thr is 6(1+2+3)hence12 ppl coz..sum of 1st 11 is 66...
There are 8 people at a party each person shakes hands with everybody else once how many handshakes are there?
28. The formula is (n * (n-1)) / 2, where n represents the number of people. You divde by 2 because each handshake covers two possibilities (ie, person #1 to person #8 is the same as person #8 to person #1).
If 20 people complete a work in 5 houshow many people are required to complete that work in 1 hour?
If the work that is required is the same amount, then the work to people ratio is 5:20. To get to 1 hour, you need to divide the amount of time by 5. Since you are going to need more people to complete the work, you then multiply the number of people by 5, and 20*5=100. Therefore, you need 100 people to complete the work in 1 hour.
How many feet in 1 yeard?
1 yard is 3 feet, if that is what you need.
If theres 66 handshakes how many people are at the party?
If there are n people who shake hands with each other exactly once, it can be observed that there are n x (n-1) handshakes. Since each handshake is counted twice here,we divide this by 2. Therefore, total number of handshakes is n(n-1)/2. In the given problem, Given: Total handshakes =66 i.e n(n-1)/2=66 n2-n =132 n2-n-132=0 (n-12)(n+11)=0 n =12 or n= -11 As handshakes cannot be negative we discard 11 . Therefore answer is , 12 people.
