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For single digit numbers in the range 0-9 there are 4 (excludes zero).
For 2 digit numbers in the range 10-99, then the even sum condition only applies when both digits are even, i.e. such numbers ending in 0,2,4,6,8 in the 20s, 40s, 60s & 80s. There are 4 x 5 = 20.
For 3 digit numbers in the range 100-999 then the even sum condition applies when (1) All 3 digits are even or (2) The first 2 digits are odd and the third digit is even.
(1) There are 4 options for the 1st digit (2,4,6,8), and 5 options for the 2nd and 3rd digits (0,2,4,6,8) There are thus 4 x 5 x 5 = 100 qualifying numbers.
(2) If the 1st and 2nd digits are odd and the 3rd digit is even then there are 5 x 5 x 5 = 125 qualifying numbers.
Total number of qualifying numbers = 4 + 20 + 100 + 125 = 249
What else can I help you with?
How many positive integers between 1000 and 9999 inclusive a are divisible by 9?
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
How many integers between 1000 and 9999 inclusive does the digit 3 occur?
There are 3168 such numbers.
How many integers between 1 to 1000 both inclusive can be expressed as the difference of squares of two non negative integers?
750
How many square numbers between 100 and 1000?
Infinitely many, since every positive number is a square of some other number. However, there are 21 perfect squares (SQUARES OF INTEGERS). From 112 to 312, inclusive.
How many positive integers less than 1000 are not divisible neither by 2 or 3?
332
What is the sum from 1000 positive integers to 1100?
The sum of the positive integers from 1,000 to 1,100 inclusive is: 106,050
How many positive integers between 1000 and 9999 inclusive a are divisible by 9?
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
How many integers between 1000 and 9999 inclusive does the digit 3 occur?
There are 3168 such numbers.
How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?
There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.
How many positive integers from 1 to 1000 inclusive are there such that is a multiple of 3 and the digit sum of is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How many 4-digit positive integers are there?
from 1000 to 9999, ie 9999 - 999 = 9000
How many positive integers n from 1 to 1000 inclusive are there such that n is a multiple of 3 and the digit sum of n is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How many four digit positive integers are there with thousands digit 2?
There are one thousand. Starting at 2000 and going to 2999
Sum of squares of first 1000 positive odd integers?
The sum of the squares of the first 1000 positive odd integers (from 12 to 19992) is 1333333000.
How many odd integers are there from 1000 through 9999?
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
How many positive integers less than 1000 have distinct digits and are even?
To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.
How many integers between 1 to 1000 both inclusive can be expressed as the difference of squares of two non negative integers?
750
