0
How many possibilities are there creating a 4 digit password using the digits 0-9 you may repeat numbers?
Wiki User
∙ 11y ago
9999
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
How many 4 digit numbers have only odd numbers?
625. Here's how:There are five odd digits {1,3,5,7,9} so our numbers will be made using only these digits. This is the same number of possibilities as if you had a base 5 number system where the allowed digits are {0,1,2,3,4}. For a 1 digit base-5, there are 5 possibilities, for a two digit base-5 there are 5² = 25 possibilities, so for a 4-digit, there are 5^4 = 625possible. This is the same number you will have with only using odd digits.
At Oxnard University a student ID consists of two letters 26 possibilities followed by four digits 6 possibilities?
Two letters = 26*26 = 676 possibilities 4 digits = 104 possibilities (if numbers such as 0000 are permitted). All in all, 6.76*106 possibilities. That should keep Oxnard University going for a few years.
How many 3 digit numbers are there made up of only odd digits?
There are 25 possibilities fitting those rules.
How many 4 digit combinations are there for numbers 0 to 9?
-- If you're allowed to repeat digits in one combination,then there are 104 = 10,000 possibilities.-- If all four of the digits must be different, then there are(10 x 9 x 8 x 7) = 5,040 possibilities.
How many whole numbers between 100 and 300 whose digits equal 11?
I assume you mean the sum of the digits.If the first digit is 1, the other two digits have to sum 10. There are 9 different possibilities for this, from 1 + 9 to 9 + 1.If the first digit is 2, the other two digits have to sum 9. There are 10 different possibilities for this, 0 + 9 to 9 + 0.Adding it all up, it seems there are 19 such numbers.
How many possibilities are there if you must create a 4 digit password using the digits 0 through 5 You may repeat numbers?
The first digit of your password can be any of the six numbers. As repetition is allowed so can the second, third and fourth so total possibilities is 6 x 6 x 6 x 6 ie 1296
How many permutations of 3 different digits are there from the ten digits 0 to 9 inclusive?
ABC A = 1,2,3,4,5,6,7,8,9; 9 possibilities B = 0,1,2,3,4,5,6,7,8,9; 10 possibilities C = 0,1,2,3,4,5,6,7,8,9; 10 possibilities So there are 9*10*10 = 900 numbers with 3 digits.
How many 6 digit numbers can be formed with 6 digits?
If the digits may not be repeated, there are 6x5x4x3x2x1 = 720 numbers, If digits can be repeated, the answer is 6x6x6x6x6x6 = 46,656 numbers If zero is ong the available digits but is excluded from the first place. 5x6x6x6x6x6=38,880 numbers
How many 2 digit numbers are there in 12345?
If the two must be different digits, then there 20 possibilities. If they can be the same one, then there are 25 possibilities.
What is the sum of all possible four digit numbers using the digits 4068?
-- If you accept 4-digit numbers with 'zero' as the first digit, thenthere are 24 possibilities, and their sum is 119,988 .-- If the first digit can't be a 'zero', then there are 18 possibilities,and their sum is 115,992 .Note: I didn't repeat any digits.-- If you allow repeated digits, and accept leading zeros, then there are 256 possibilities,and their sum is 1,279,872.-- If you allow repeated digits but not leading zeros, then there are only 192 possibilities,and their sum is 1,247,904.
How many 4 digit numbers have only odd numbers?
625. Here's how:There are five odd digits {1,3,5,7,9} so our numbers will be made using only these digits. This is the same number of possibilities as if you had a base 5 number system where the allowed digits are {0,1,2,3,4}. For a 1 digit base-5, there are 5 possibilities, for a two digit base-5 there are 5² = 25 possibilities, so for a 4-digit, there are 5^4 = 625possible. This is the same number you will have with only using odd digits.
At Oxnard University a student ID consists of two letters 26 possibilities followed by four digits 6 possibilities?
Two letters = 26*26 = 676 possibilities 4 digits = 104 possibilities (if numbers such as 0000 are permitted). All in all, 6.76*106 possibilities. That should keep Oxnard University going for a few years.
Which numbers have the greatest number of significant numbers?
The significant digits in a number can be arbitrarily small or large in number, according to the method of creating them.Numbers that can have an infinite number of possible significant digits are called transcendental numbers.
How many 3 digit numbers have at least one repeated digit?
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
How many three digit numbers have three distinct digits?
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
How many 3 digit numbers are there made up of only odd digits?
There are 25 possibilities fitting those rules.
How many 10 digit numbers contain no repetition of digits?
This is a permutation problem. The digits are: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. The 1st digit has 9 possibilities (it cannot be zero). Thus, there are 9(9P9) = 9(9!) = 9(362,880) = 3,265,920 such numbers, because: The 2nddigit has 9 possibilities (because we are left with 9 digits). The 3rd digit has 8 possibilities. The 4th digit has 7 possibilities. The 5thdigit has 6 possibilities. The 6thdigit has 5 possibilities. The 7thdigit has 4 possibilities. The 8thdigit has 3 possibilities. The 9thdigit has 2 possibilities. The 10thdigit has 1 possibility. so that, 9*9*8*7*6*5*4*3*2*1= 3,265,920.
