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What is the equation to determine number of possible lock combinations?
In the simplest case, if A is the number of values a single element of a combination can have, and N is the number of elements in the combination, then the number of possible lock combinations is AN. For example: if you have a lock with a 4-digit numerical combination, any combination has 4 elements - the digits. Each digit can have 10 values - 0 through 9. So the total number of lock combinations is 104 or 10000. Another example: if you have the typical rotating combination padlock, a combination consists of three numbers, each of which can be 0-39. So the total number of combination shere is 403 or 64000. The calculation gets more complicated if the same number can't appear twice in the combination. In that case, there are A values for the first element, but only A-1 values for the second, A-2 values for the third, and so on. The formula in this case is A(A-1)(A-2)(...)(A-N+1) which can be written more concisely as A!/(A-N)!. For example: if you have the same rotating combination padlock as above, but know that the numbers in the combination are all different, there are 40*39*38 or 59280 possible combinations.
Which numbers add up to 142?
To find which numbers add up to 142, we need to consider all possible combinations of numbers that sum to 142. One way to approach this is by using a systematic method such as trial and error or algebraic equations. For example, one possible combination is 70 + 72 = 142. Another combination could be 50 + 92 = 142. It's important to note that there are multiple combinations of numbers that can add up to 142.
What are the possible different combinations of numbers in four digits?
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.
What times what equals 756?
There are infinitely many possible answers. For example,3 * 252or 30 * 25.2or 300 * 2.52There are infinitely many possible answers. For example,3 * 252or 30 * 25.2or 300 * 2.52There are infinitely many possible answers. For example,3 * 252or 30 * 25.2or 300 * 2.52There are infinitely many possible answers. For example,3 * 252or 30 * 25.2or 300 * 2.52
If you flipped a coin ten times what is the probability you would get five heads?
We need to calculate two things:How many possible possible series of 10 coin flips are there? As we flip 10 times and each time we can have either heads or tails we have 2 by the power of ten possibilities, or a total of 1024 unique possible series.Now, how many of those series have exactly five heads and five tails? Lets assume we have ten "pre filipped" coins at hand - 5 tails and 5 heads. How many possible combinations are there. Well, if they were all different, you would have 10! (10 factorial = 10*9*8*7*6*5*4*3*2*1) possibilities.How ever, the 5 heads are identical and so are the 5 tails, so if I interchange the locations of two coins that are both heads for example I still get the exact same series. There are 5! possible heads combinations, and 5! tails combinations.Thus, the total number of unique combinations is 10!/(5!*5!) which happens to be 252.So, out of 1024 possible series, 252 contain exactly 5 heads.The probability thus is 252/1024=0.24609375 (roughly 25%)
How many possible combinations are there with 7 numbers 1 through 49 but only the combinations that begin with 1 example 1234567 134567 14567 So all possible 7 digit combinations that begin with 1?
the equal nukber would be 1000987654 but if you put it that way you will lose the stautus chart and it will mess you up i am a math teacher for 12 grade i know my stuff
What is a circular combination?
^ Thanks for helping kanika! I was wondering whether there is a formula to derive the number of possible combinations (for a circular arrangement). If you do know the answer, please help!
How many combinations of 3 numbers are there?
6 for example, 123 123 132 321 213 231 312 * * * * * WRONG. Those are permutations, not combinations. There are 8 possible combinations: 123 12 13 23 1 2 3 and finally, the null combination.
What is the equation to determine number of possible lock combinations?
In the simplest case, if A is the number of values a single element of a combination can have, and N is the number of elements in the combination, then the number of possible lock combinations is AN. For example: if you have a lock with a 4-digit numerical combination, any combination has 4 elements - the digits. Each digit can have 10 values - 0 through 9. So the total number of lock combinations is 104 or 10000. Another example: if you have the typical rotating combination padlock, a combination consists of three numbers, each of which can be 0-39. So the total number of combination shere is 403 or 64000. The calculation gets more complicated if the same number can't appear twice in the combination. In that case, there are A values for the first element, but only A-1 values for the second, A-2 values for the third, and so on. The formula in this case is A(A-1)(A-2)(...)(A-N+1) which can be written more concisely as A!/(A-N)!. For example: if you have the same rotating combination padlock as above, but know that the numbers in the combination are all different, there are 40*39*38 or 59280 possible combinations.
How many combinations are there in swertres?
You need to specify how many characters, form the eight, are to be in the combinations. For example, there is only 1 combination of 8 characters.
What are all the possible allele combination that could be formed if this cell undergoes meiosis?
During meiosis, the possible allele combinations that could be formed depend on the number of alleles present for each gene. If the cell is diploid (2n), then there are 2^(n) possible combinations, where n is the number of alleles for each gene. For example, with two alleles (A and B) for a single gene, the possible combinations are: AB, Ab, aB, and ab.
Can a remainder be a three diget number?
Yes Example: 1234567 divided by 1000 has a remainder of 567.
How many combinations can you make with 7 12 5 and 3 objects?
It depends on the sizes of the combinations. For example, there is only one combination of 7 things out of 7, but there are 21 combinations of two items.
How do you do a password on 10 characters?
Mix as many combinations as possible. Here is one example: f_@mW^1O3+
How do iPhone landline Ireland from UK?
00353 (then the county code example 01-Dublin, but drop the 0) example 00353(1)1234567
How you written your mobile no in international forms?
Plus, country code, area code, number For example: +1 555 1234567
What are the possible combinations that equal the volume of 78 I have to use the factors of 78 to come up with the combinations for example 1x1x78 equals 78 or 2x3x13 equals 78 PLEASE HELP?
78C3 = 76,076 possibilities
