the equal nukber would be 1000987654 but if you put it that way you will lose the stautus chart and it will mess you up i am a math teacher for 12 grade i know my stuff
The is answer is Pie because when you pull the numbers to a negative loop you will get infinity and when you get infinity you will and 8 and when you do 8 plus infinity is pie i know cause i am a teacher who has been teaching science for 67 years
There are 167960 combinations.
4
Just 1.
To calculate the number of combinations possible with 8 numbers in a seven-number combination, you would use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 8 and r = 7. Plugging these values into the formula, you get 8C7 = 8! / (7!(8-7)!) = 8. Therefore, there are 8 possible combinations with 8 numbers in a seven-number combination.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
10,000
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
Not repeating, it is 7*6*5*4 which is 840 ways ---- There are 7 choices for each of four digits, right? 74 = 2401
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.