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Q: If a division problem has divisor of 9 what is the greatest possible remainder?

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The greatest integer remainder for a division sum with a divisor of 63 would be 62 - for a number one fewer than an integer multiple of 63 - for example, 125/63 = 1 remainder 62.

16

12-1, that is, 11.

456y67783

the parts of division problem are : dividend , divisor , quotient and remainder . where : dividend = quotient * divisor + remainder

Related questions

The greatest integer remainder for a division sum with a divisor of 63 would be 62 - for a number one fewer than an integer multiple of 63 - for example, 125/63 = 1 remainder 62.

62

16

75

7

24. It is always one less than the divisor.

12-1, that is, 11.

456y67783

The greatest possible remainder for 76 is to be divided by 2 leaving the result of 38. Thank you!

What is the largest remainder possible if the divisor is 10

the parts of division problem are : dividend , divisor , quotient and remainder . where : dividend = quotient * divisor + remainder

If the remainder were greater than the divisor, you'd be able to take another divisor out of it.

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