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Infinitely many.


Select any number between 0 and sqrt(28) and call it W.

Then let L = 28/W.


A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.



Infinitely many.


Select any number between 0 and sqrt(28) and call it W.

Then let L = 28/W.


A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.



Infinitely many.


Select any number between 0 and sqrt(28) and call it W.

Then let L = 28/W.


A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.



Infinitely many.


Select any number between 0 and sqrt(28) and call it W.

Then let L = 28/W.


A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.

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11y ago
Infinitely many.


Select any number between 0 and sqrt(28) and call it W.

Then let L = 28/W.


A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.

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Q: How many rectangles are possible for 28 square units?
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