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How many five-digit counting numbers contain at least one 6?
46000
How many 3 digit numbers contain the digit 2 at least once?
252
How many 3 digit numbers are there that contain at least 1 seven?
252
If the houses on main street are numbered 1 to 150 how many house numbers contain a least one digit 91 and 4?
10293330201309i31841481389
How many 3 digit numbers contain the digit 3 at least once?
172==============================Another contributor was amazed:Wow ! That's a neat little problem.Let's see . . . . .-- There are three ways to have a single 3 in the number: 3xx, x3x, and xx3.For 3xx, there can be 81 different numbers. (2nd and 3rd digits can't be a 3. 9x9=81.)For x3x, there can be 72 numbers. (1st can't be 0 or 3. 3rd can't be a 3. 8x9=72.)For xx3, there are also 72. (1st can't be 0 or 3. 2nd can't be a 3. 8x9=72.)So far, we have 81+72+72 = 225 possibilities, with a single 3 in each one.-- There are three ways to have two 3s in the number: 33x, 3x3, and x33.For 33x, there can be 9 different numbers. (3rd digit can't be a 3.)For 3x3, there can be 9 numbers. (2nd digit can't be a 3.)For x33, there are 8 numbers. (1st digit can't be a 0 or a 3.)So we have 9+9+8 = 26 more possibilities.-- There is only one way to have three 3s in the number: 333.That's one more possibility.So the total number of 3-digit numbers where at least one of the digits is a 3 is225 + 26 + 1 = 252 all together.
How many five-digit counting numbers contain at least one 6?
46000
How many seven digit numbers contain the number seven at least once?
4,748,472 Confirmed using the following C# function string sTemp; int total = 0; for (int i = 1000000; i < 10000000; i++) { sTemp = i.ToString(); if (sTemp.Contains("7")) { total++; } } label1.Text = total.ToString();
How many 3 digit numbers contain the digit 2 at least once?
252
How many integers from 1 to 100000 contain the digit 6 at least once?
Oh, isn't that a happy little question! To find the number of integers from 1 to 100,000 that contain the digit 6 at least once, we can think about it like painting a beautiful landscape. We can first count the numbers that do not have the digit 6, which are the numbers from 1 to 9,999. There are 10,000 numbers that do not have the digit 6. Then, we subtract this from the total numbers from 1 to 100,000 to find the answer. Happy counting!
How many 3 digit numbers are there that contain at least 1 seven?
252
How many three digit numbers contain at least two sevens?
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
What proportion of the first 10000 natural numbers contain a 5?
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
What is the least possible sum of two 4-digit numbers?
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
Which digit is least used while counting from 1 to 100?
Zero.
What is the least common multiple of the first twelve counting numbers?
The LCM of the first twelve counting numbers is 27720
If the houses on main street are numbered 1 to 150 how many house numbers contain a least one digit 91 and 4?
10293330201309i31841481389
How many 3 digit numbers contain the digit 3 at least once?
172==============================Another contributor was amazed:Wow ! That's a neat little problem.Let's see . . . . .-- There are three ways to have a single 3 in the number: 3xx, x3x, and xx3.For 3xx, there can be 81 different numbers. (2nd and 3rd digits can't be a 3. 9x9=81.)For x3x, there can be 72 numbers. (1st can't be 0 or 3. 3rd can't be a 3. 8x9=72.)For xx3, there are also 72. (1st can't be 0 or 3. 2nd can't be a 3. 8x9=72.)So far, we have 81+72+72 = 225 possibilities, with a single 3 in each one.-- There are three ways to have two 3s in the number: 33x, 3x3, and x33.For 33x, there can be 9 different numbers. (3rd digit can't be a 3.)For 3x3, there can be 9 numbers. (2nd digit can't be a 3.)For x33, there are 8 numbers. (1st digit can't be a 0 or a 3.)So we have 9+9+8 = 26 more possibilities.-- There is only one way to have three 3s in the number: 333.That's one more possibility.So the total number of 3-digit numbers where at least one of the digits is a 3 is225 + 26 + 1 = 252 all together.
