46000
252
252
10293330201309i31841481389
To find the number of 3-digit numbers that contain the digit 3 at least once, we can use the concept of complementary counting. There are a total of 900 three-digit numbers (ranging from 100 to 999). To find the numbers that do not contain the digit 3, we calculate the numbers with digits 0, 1, 2, 4, 5, 6, 7, 8, and 9 in each place. There are 8 choices for each place, so the total number of three-digit numbers without the digit 3 is 8 x 9 x 9 = 648. Therefore, the number of three-digit numbers that contain the digit 3 at least once is 900 - 648 = 252.
46000
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
252
252
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
Zero.
The LCM of the first twelve counting numbers is 27720
10293330201309i31841481389
To find the number of 3-digit numbers that contain the digit 3 at least once, we can use the concept of complementary counting. There are a total of 900 three-digit numbers (ranging from 100 to 999). To find the numbers that do not contain the digit 3, we calculate the numbers with digits 0, 1, 2, 4, 5, 6, 7, 8, and 9 in each place. There are 8 choices for each place, so the total number of three-digit numbers without the digit 3 is 8 x 9 x 9 = 648. Therefore, the number of three-digit numbers that contain the digit 3 at least once is 900 - 648 = 252.
100,000