11, 12, 13, 14, 15, 16, 17, 18, 19
As shown above, the digit 2 is only written once.
You can write that as 1 teaspoon, or 1.0 teaspoon.
93 and 7 would be an example.
6 times
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
I believe that the numbers One and Nine fit the bill as they would be 1x9= 9 and 1+9=10.
189 pennies.
You can write that as 1 teaspoon, or 1.0 teaspoon.
That looks like it should be the same as 10 times (the number of times the digit 1 occursin the units place in the numbers from 10 to 100), which would work out to 90 .
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
You would use a zero 11 times in writing the numbers 1 to 100 once - so doing it five times gives you 55 zeros.
£1.92 (or $1.92, of you mean American penny)
Without restrictions, it was would numbers 000-000-0000 through 999-999-9999. So that would be 9,999,999,999 + 1 = 10 billion different 10-digit phone numbers. Ex: If there existed single digit phone numbers, there would be 10, because the digits are 0 through 9. If there existed only double digit phone numbers, then it would be 00 through 99 which would be 100 total two-digit numbers. Therefore the total possible combinations for an X digit phone number would be: 10^X
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
Technically, that is not possible. A digit is another word for a number and it would be impossible for a single number to contain ten numbers.
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
93 and 7 would be an example.
10,000 of them, from 0000 to 9999. However, most people would not count numbers with leading 0s, so that there would be 9000 4-digit numbers.