39
48
57
66
75
84
93
I see 7. I think that's all of them.
1
2. They are 10 and 11
7: 93, 39, 84, 48, 75, 57, 66.
Hello
13
23
13
4
5/5
There are 5460 five digit numbers with a digit sum of 22.
There are 60480 numbers.
There are 5760 such numbers.
36 of them.
There are 5! = 120 such numbers.
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
Twelve of them.
With 123 digits you can make 123 one-digit numbers.
There are 5460 five digit numbers with a digit sum of 22.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
7 two-digit numbers.
There are 90000 5-digit numbers.
757
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 5*4*3 = 60 such numbers.