You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
8 ! = 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1 = 40320
Answerthe answer is 24 WHICH is the result of the multiplication: 4x 3 x 2 x 1 = 24. You can try it practically as: Numbering books as A,B, C, and D then the variations are:ABCDABDCBACDBADCCDABCDBADCABDCBABCADBCDACBADCBDAADBCADCBDABCDACBBDACBDCADBACDBCAACBDACDBCABDCADB
One row of 5 different brands with each type being represented can be arranged in 5x4x3x2x1= 120 ways
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
6 ways
24 ways
792 different groups of 5 books, in 95,040 different sequences.
There are 2*5! = 240 ways.
The number of ways that 15 books can be arranged on a shelf is the same as the number of permutations of 15 things taken 15 at a time. This is 15 factorial, or 15!, and is 1,307,674,368,000.
it depends on the shelf of course
The number of ways 7 different books can be stacked on a shelf is the same as the number of permutations of 7 things taken 7 at a time, which is 7 factorial, or 5040.
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120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
30 ways.