120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
240. 120 ways with the books stacked verticly, and 120 ways with the books stacked horizontaly, or one on top of the other.
8 ! = 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1 = 40320
3 from 6 = 6 x 5 x 4 x 3 x 2)/3 x 2 x 3 x 2 = 20 different sets of 3 which can then be arranged 3 x 2 different ways so the answer is 120. See if you can find them all!
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120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
30 ways.
The answer to this one is 24. You can do this mathematically by 4*3*2*1.
10!
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Yes. They are real.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
The answer would be 7! or (7*6*5*4*3*2*1)=5040
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
792 different groups of 5 books, in 95,040 different sequences.