None.
By definition a hole is an empty space.
It is: 2m times 2m is equivalent to 4m^2
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
The rate for one man to finish a 2mx2mx2m whole is... 1 man = 8m3 per day At the same rate three men can each do a 2mx2mx2m whole. This is how much they altogether can do in one day. 3 men = 24m3 per day The whole they have to dig is this size. 4mx4mx4m which is 64m3 Since three men can do 24m3 per day it will take them 2 days and 16 hours to dig a 64m3 hole.
40 cubic meters
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
It is: 2m times 2m is equivalent to 4m^2
4m
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
4 cubic meters.
40m^3
The rate for one man to finish a 2mx2mx2m whole is... 1 man = 8m3 per day At the same rate three men can each do a 2mx2mx2m whole. This is how much they altogether can do in one day. 3 men = 24m3 per day The whole they have to dig is this size. 4mx4mx4m which is 64m3 Since three men can do 24m3 per day it will take them 2 days and 16 hours to dig a 64m3 hole.
To multiply (4m) by (2m), you multiply the coefficients and the variables separately. The coefficients (4) and (2) multiply to (8), and (m \times m) equals (m^2). Therefore, (4m \times 2m = 8m^2).
Well, darling, if the length of your rectangle is 4m and the width is 2m, then the perimeter is simply calculated by adding up all the sides, which gives you 4m + 4m + 2m + 2m, totaling 12 meters. Voilà, there's your answer!
40 cubic meters
6m + 5n - 4m + 7n = 2m + 12n
2m + 13n
A rectangle is one of the six faces of a cuboid (a rectangular parallelepiped). The area of a rectangle 4m long and 2m wide is 8m2. Multiply this by the thickness (or depth) of the cuboid to obtain its volume.