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A water hose is a cylinder, and since the volume of a cylinder is pi*r^2*height, we can calculate the volume of the water hose by finding the radius and height. A 3 inch hose has a radius of 1.5 inches, and 50 ft is equal to 600 inches, so 1.5^2 is 2.25, and 2.25*600 is 1,350. Finally we multiply by Pi to get approximately 4,239 cubic inches. Since 1 cubic inch is equal to 0.00432 gallons, there are 18.3506 gallons.
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How much does a 100 ft section of 2.5 inch in diameter fire hose weigh with water?
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.
Weight of 50 ft section of 3 inch fire hose?
Weight of 50ft section of 3 inch hose with water in it?
How many gallons of water in a 2.5 inch hose 100 feet long?
There need not be any water at all in the hose! The capacity of the hose is 3.41 cubic feet.
How much water does a 100 foot hose with 1.5 inch diameter hold?
To calculate the volume of water held by the hose, we first need to find the cross-sectional area of the hose. The formula for the area of a circle is A = πr^2, where r is the radius of the hose (which is half the diameter). In this case, the radius is 0.75 inches. Converting the radius to feet (0.0625 feet), we can calculate the area of the hose's cross-section. Multiplying the cross-sectional area by the length of the hose (100 feet) gives us the volume of water held by the hose.
How much does a 50 ft section of 5 inch diameter fire hose weight?
109 lbs with no water
