6 times ?2 ? equals a number.
Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
6AG + N2 --> 2AG3N is the balanced equation.
declare n1 number; n2 number; n3 number; begin n1:=3 n2 :=5 n3:= sum(n1,n2); dbms_output.put_line( n3); end
n= sqrt 225 = 15
n2 = 10n + 56 Subtract (10n + 56) from each side: n2 - 10n - 56 = 0 Now you have something on the left side that you can factor: (n - 14) (n + 4) = 0 n = +14 n = - 4
n2 - 10n + 21 = 0 Two numbers that sum to -10 and multiply to 21 are -3 and -7 So (n - 3)*(n - 7) = 0
-n(n + 10) or n(-n - 10)
5(n2 + 2n + 4)
n1 has 1 n2 has 4
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
0.5*(n2-3n) where n equals the number of sides of the polygon
If: n2 = 19 Then: n = the square root of 19.
6 times ?2 ? equals a number.
Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
N2
1/2*(n2-3n) = diagonals when n equals number of sides.