I take it you mean if 2a - 3b = 11 an a+b = 7 then find the value of a and b.
The problem with this site is that the questions can't contain things like the equal sign
To solve a problem like this we need to get two of the letter values to be the same, and then we can subtract one equation from the other.
so, if we multiply the second equation by -2 we get
-2a - 2b = -14
No to that we add
2a - 3b = 11
and we get
-5b = -3
so b = 3/5
Now we can replace the b in the second equation and we get
a + 3/5 = 7
So we can see that a must equal 62/5
and if we put these values into the first equation the two sides of the equation should balance...
2 (62/5) - 3(3/5) should equal 11... so we'll multiply the values and check
2 (62/5) = 124/5
and
3(3/5) = 9/5 = 14/5
and indeed 124/5 - 14/5 does indeed = 11.
You can, instead, find the log of the ratio. Thus: log(A) - log(B) = log(A/B)
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The slope is[ (y-value of 'b') - (y-value of 'a') ] / [ (x-value of 'b') - (x-value of 'a') ]
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2a+b=2a+b. Without a value for a and b, the expression has no value.
That depends what either the value of a or the value of b is.
times b by a
The value of m is the slope and the value of b is the y intercept.
Find the largest of two, then find the largest of that value and the third value. int* max (int* a, int* b) { return (a*) > (b*) ? a : b; } int* max_of_three (int* a, int* b, int* c) { return max (max (a, b), c); }
To find A as a percentage of B, calculate 100*A/B To find A as a percentage change from B, calculate 100*(A/B -1) or, equivalently, 100*(A - B)/B. B should be positive else you will need great care in interpreting the result.
a-b=-2 a+b+10 solves simultaneusly a=4 b=6
You can, instead, find the log of the ratio. Thus: log(A) - log(B) = log(A/B)
The main use for a logarithm is to find an exponent. If N = a^x Then if we are told to find that exponent of the base (b) that will equal that value of N then the notation is: log N ....b And the result is x = log N ..........b Such that b^x = N N is often just called the "Number", but it is the actuall value of the indicated power. b is the base (of the indicated power), and x is the exponent (of the indicated power). We see that the main use of a logarithm function is to find an exponent. The main use for the antilog function is to find the value of N given the base (b) and the exponent (x)
If these two sides are opposite to these angles, and you know one of the angles, you can use the Law of Sines to find the other angle. For example, in the triangle ABC the side a is opposite to the angle A, and the side b is opposite to the angle B. If you know the lengths of these sides, a and b, and you know the measure of the angle B, then sin A/a = sin B/b multiply by a to both sides; sin A = asin B Use your calculator to find the value of arcsin(value of asin b), which is the measure of the angle A. So, Press 2ND, sin, value of asin B, ).
lil tj
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dim a,b,c a=cint(inputbox("enter value for a")) b=cint(inputbox("enter value for b")) c=cint(inputbox("enter value for c")) if((a>b)and(a>c)) then msgbox "greatest number is a="&a else if ((b>a)and(b>c)) then msgbox "greatest number is b="&b else msgbox "greatest number is c="&c end if end if