2x - 3y = -1
3x + 2y = 31
eqn(1) * 2: 4x - 6y = -2
eqn(2) * 3: 9x + 6y = 93
Add the two: 13x = 91
Divide both sides by 13: x = 7
Substitute this value of x into eqn(1): 14 - 3y = -1
Add 3y to bot sides: 14 = -1 + 3y
Add 1 to both sides: 15 = 3y
Divide both sides by 3: 5 = y
So the solution is x = 7, y = 5
What is the value of x in the equation 2x + 3y = 36, when y = 6?
n = 3/2, n = 2
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
They are identities because they are true for ALL values of w and x.
2048
That is an impossible equation, because it is stating that m has two values.
x^2y(2x + y)
x=-3y=4
Put the equation in this form: y=mx+b. Then m will be the slope. 2x3y+6=0 2x3y=-6 3y=-6/2x y=-2/2x y=-1/x This equation does not describe a straight line, but rather, it describes a curve.
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
-2
The values are: x = -6 and y = 10
Decomposition into decimal digits (or separating out into place values).
Any two values which total 25
That depends what the values of k and b are.
144 (square the first value and add the product of the two values). In the statement 7 + 6 should = 91, not 63, which would be 7 + 2.
n = 3/2, n = 2
The values of a and b are 7 and 18 or 18 and 7