Line segment RT
If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
11
Given ST=2x-10,RS=2x_5,andRT=3x+1,determine the numerical length of RT
Answering this question might be possible if we knew something ... anything ... about the relationships among RS, ST, SL, and KT. Since we don't, it's not. On the remote chance that there might have been some kind of drawing printed next to this question wherever it was copied from, it's worth mentioning that if the drawing were not needed in order to answer the question, then it would not have been printed there, because every graphic in a book increases the cost of publishing the book. If there's a drawing there, then you need it in order to answer the question, and if you plan on trying to hit somebody else up for the answer, then he's going to need the drawing too.
r = 3 s = 5 t = 6 rs = 3x5 = 15 rt = 3x6 = 18 st = 5x6 = 30
michael jackson
Line segment RT
Yes.
yes
If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
11
The angle opposite side RT = 12 will have the smallest measure
It is angle RST.
rhombus a rectangle and a square
RS can have any value in the range [25, 55].
s - r = 18, so s = 18 + r: t - r = 4(t - s) is t - r = 4(t - 18 + r) ie t - r = 4t - 72 + 4r 3t = 72 - 5r Possible answers: t = 19, r = 3, rt = 16, st = 4; r/s/t = 0, 12, 16 x 1.5 gives 0, 18, 24 t = 14, r = 6, rt = 8, st = 2; r/s/t = 0, 6, 8 x 3 also gives 0, 18, 24 t = 9, r = 9 t = 4, r = 12 The last two are not in fact possible as t must exceed r. The distances starting from r at 0, are rs = 18, st = 6 and rt = 24 The above is unnecessarily complicated! If s is between r and t and rt is 4 times st then rs must be 3 times st. rs is 18 so st is 6 and rt 24. Simple!