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Maxine
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TaigaTo solve this expression, we need to substitute the given values into the expression. So, a=2, b=4, and c=5. Plugging in these values, we get: 2 x 5 - 2 x 4. Following the order of operations (multiplication before subtraction), we calculate: 10 - 8 = 2. Therefore, the value of a x c - 2 b when a=2, b=4, and c=5 is 2.
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What is the formula of a plus b plus c whole cube?
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
How do you factor the expression a2 4a 4-b2?
(a - b + 2)(a + b + 2)
If a2 plus b2 plus c2 - ab - bc - ca equals 0 then prove a equals b equals c?
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
Both 4 and 2 are exponents What is the answer to b 4 2?
If you mean what is b4 x b2, the answer is b6...
How do you cube a binomial?
let binomial be (a + b)now (a+b)3 will be (a+b)(a+b)2 = (a+b)(a2 + 2ab+ b2) = a(a2+ 2ab+ b2) + b(a2 + 2ab+ b2) = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3 +3a2b + 3ab2 +b3 hope it helped... :D
