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2 x 5- 8 = 2

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Q: If a2 b4 c5 what is a x c - 2 b?
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How do you factor a8-b8 completely?

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How do you factor a4 - b4 completely?

To factor a^4 - b^4 completely, you can use the formula for the difference of squares, which states that a^2 - b^2 = (a + b)(a - b). In this case, a^4 - b^4 is a difference of squares twice: (a^2)^2 - (b^2)^2. So, you can factor it as (a^2 + b^2)(a^2 - b^2). Then, factor a^2 - b^2 further using the difference of squares formula to get (a^2 + b^2)(a + b)(a - b), which is the complete factorization of a^4 - b^4.


How do you factor completely a8-b4?

(a^2 - b)(a^2 + b)(a^4 + b^2)


How is the expansion of algebraic expressions done?

There are 3 main rules for expansion of algebraic expressions. They are as follows: 1) a2 _ b2 = (a-b) (a+b) 2) (a+b)2 = a2 + 2ab +b2 3) (a-b)2 = a2 - 2ab +b2


How the differences of the two squares a2-b2(a b)(a-b) relates to the product of a complex number and it's conjugate?

(a+b)(a-b) = a2 - b2 if we replace b by ib in this equation, then we get: (a+ib)(a-ib) = a2 - (ib)2 = a2 + b2 if z=a+ib then its conjuguate is a-ib and their product is a2 + b2


A plus b equals 4 and ab equals 2 then a4 plus b4 equals?

1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)


What is the formula of a plus b plus c whole cube?

a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc


Is a squared plus b squared the same as a plus b squared?

No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2


How do you factor the expression a2 4a 4-b2?

(a - b + 2)(a + b + 2)


How do you expand A-B times A squared AB-B squared?

The question is a little unclear. If you mean: (A - B) x A2, then the answer is: A3 - (B x A2) (or, more simply, A3-BA2) If you mean: ((A - B) x A)2, then the answer is: (A2 - AB)2 which becomes A4 - 2A3B + A2B2


What is the firing order for 69 Rolls-Royce silver shadow?

Right Bank A, Left Bank B A1 B1 A4 B4 B2 A3 B3 A2


What is the firing order on a 1976 Rolls-Royce silver shadow?

Right Bank A, Left Bank B A1 B1 A4 B4 B2 A3 B3 A2