21.21 feet
The diameter length of the circle would be the same as the side length of the square. If a is the side of the square, then the radius is a/2, and the area of the circle would be (1/4)(pi)(a^2).
A 48-inch diameter circle has an area of: 12.57 square feet.
Yes, the circle's diameter is not bigger than the square base length.
Diameter = 1/2 of the circle's radius. Diameter = 2 times the square root of (the circle's area/pi) Diameter = the circle's circumference/pi
The area of a circle with a diameter of 16 inches is: 201.1 square inches.
Assuming that the 14 inch box is square, you could fit a circle inside with a 14 inch diameter.
The largest diameter you can inscribe in a circle is a square. The square's diagonal is equal to the diameter of the circle; the length of the side of the square is therefore equal to the circle's diameter, divided by the square root of 2.
The diagonal of the square.
The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.
The same as half the side of the square, as the radius of the circle is half its diameter, and the diameter of the circle is equal to the side of the square.
If the circle inscribes the square, the diameter equals the square's side length. In this case, 16mm.
The diameter length of the circle would be the same as the side length of the square. If a is the side of the square, then the radius is a/2, and the area of the circle would be (1/4)(pi)(a^2).
The diameter of the circle is congruent to the length of the diagonal of the inside square. If you know the length of one side of the square, you can use pythagorean's theorem to solve for its diagonal (hypotenuse) and thusly the square's diameter.
The largest square that could fit in a circle of diameter 10 inches has dimensions 5sqrt(2) inches by 5sqrt(2) inches.
Measure the distance from top left corner of square (or top right) to the bottom right corner of square( or bottom left) to get the diameter of the circle. Then calculate the circumference from that figure.
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
A circle with a diameter of 2 is the guiding cynosure when Pi is the square of all possible circles: If the square root of Pi defines the side of a square and that square can be inscribed within a circle or enclose a circle, then the diameters of all possible circles between the largest and smallest include the circle of which Pi is its perfect square (a diameter of 2).