Yes, the circle's diameter is not bigger than the square base length.
A square with sides of 0.4985 units will fit in the circle.
21.21 feet
3.1416 times. This figure is normally known as pi.
The square's sides will be the sqrt 2 = about 1.414 inches.(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)diagonal = (sq rt 2) x sidediameter = sq rt (s^2 + s^2).2 inches = sq rt (2 s^2)2 inches - (sq rt 2) x s2 inches = 1.414 sand s = 1.414
Circle
Assuming that the 14 inch box is square, you could fit a circle inside with a 14 inch diameter.
Yes if 1.5 is the diameter of the circle but no if 1.5 is the radius of the circle.
The largest square that could fit in a circle of diameter 10 inches has dimensions 5sqrt(2) inches by 5sqrt(2) inches.
A square with sides of 0.4985 units will fit in the circle.
The largest square that can fit inside a 36-inch diameter circle has its corners touching the circle. The diagonal of the square equals the diameter of the circle, which is 36 inches. Using the relationship between the side length (s) of the square and its diagonal (d) (where (d = s\sqrt{2})), the side length of the square is (s = \frac{36}{\sqrt{2}} \approx 25.45) inches. Thus, the side of the largest square that fits inside the circle is about 25.45 inches.
15
21.21 feet
16x16 inch tiles are square. If you place them on a circle, the edges will hang off, so we first need to find the size of the largest square that will fit in the circle. The largest square can be made of four isosceles triangles whose equal sides are equal to the length of the radius, so the area of the contained square is 2r2. An 11-foot diameter circle has a radius of 5.5 feet, so the square has an area of 2(5.5)2 = 60.5 square feet, or 60.5 * 122 square inches = 8712 square inches. The 16x16 tiles are 256 square inches, so 8712 / 256 = 34.03125 tiles that fit completely in the circle.
Yes because the diameter of the circle is less than the sides of the square.
12 inches.
It depends on the diameter of the circle and the width of the square, if they are the same then the answer is no. If you draw yourself a square then inscribe a circle with a radius of half the length of a side of the square, the circle will fit inside the square but the corners of the square will be outside the circle. Thus by inspection the area of the square is larger than the area of the circle.
Is the 8 inches of the pizza the diameter or circumference? Is the 8-inches of the box the area of side length? If the diameter if the pizza and the side length of the box are both 8-inches, then the pizza will barely fit. If the circumference of the pizza is 8 inches, that means that the diameter is 8/pi = 2.546..... and that would fit in a box with side lengths of 8-inches. If the box's area is 8-inches, that means the side lengths are the square root of 8=2.828.... A pizza of diameter 8-inches won't fit, but a pizza of circumference of 8-inches will.