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If segment ad is perpendicular to segment ce which angles are complementary angles?
Wiki User
∙ 9y ago
Amc
Wiki User
∙ 9y ago
Anonymous
angle AMG and EMG
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How do you find base of triangle?
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
Which quadrilaterals have diagonals that bisects each other?
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Using one line segment make 10 10 10 equal 950?
hello people that answer is 10 TO 10 AD A LITTLE HORIZONTAL LINE AT THE TOP OF THE SECOND 1
Why are opposite angles in a parallelogram equal?
Opposite angles of quadrilaterals in general can vary over quite a range of degrees. In order for a quadrilateral to be a parallelogram, two sets of parallel lines intersect. Imagine a parallelogram resting on its base. Focus on one of the base interior angles. Now flip the parallelogram so that its top is now the base. The shapes will be completely congruent, both in angle size and lengths of sides. Parallelogram is simply a special class of quadrilateral, and this property is part of how parallelograms are defined. Alternative Answer: It is rather difficult to prove a geometric proposition while working within the limitations of this browser! But here goes: Call the parallelogram is ABCD with AB parallel to DC horizontal, and AD parallel to BC. Consider AD and BC which are parallel, with transversal DC. Then the interior angles on the same side are supplementary. That is, angles ADC and DCB are supplementary. Now consider AB and DC which are parallel, with transversal AD. Then the interior anlges on the same side are supplementary. That is, angles BAD and ADC are supplementary. So in the above two paragraphs we have shown that angles ADC + DCB = BAD + ADC therefore angle DCB = angle BAD [subtracting angle ADC from both sides] that is, one pair of opposite angles are equal. You can prove the other pair is equal either by the fact that they are supplementary to these, or by the symmetry of the argument.
What is the proof of Basic propotionality theorem?
given: A triangle ABC with DE drawn parallel to BC construction: produce EM and DN perpendicular to AD & AE respectively. Join DC & BE. proof: I'll give it whenever i come to this site the next time
If segment AD perpendicular segment CE m angle 1 m angle 6 and m angle 1 37 find m angle GMD?
143
Angle bisector of angleA of triangleABC is perpendicular to BC prove it is isosceles?
Let D represent the point on BC where the bisector of A intersects BC. Because AD bisects angle A, angle BAD is congruent to CAD. Because AD is perpendicular to BC, angle ADB is congruent to ADC (both are right angles). The line segment is congruent to itself. By angle-side-angle (ASA), we know that triangle ADB is congruent to triangle ADC. Therefore line segment AB is congruent to AC, so triangle ABC is isosceles.
What is meaning of perpendicular?
Exactly upright or vertical; pointing to the zenith; at right angles to the plane of the horizon; extending in a right line from any point toward the center of the earth., At right angles to a given line or surface; as, the line ad is perpendicular to the line bc., A line at right angles to the plane of the horizon; a vertical line or direction., A line or plane falling at right angles on another line or surface, or making equal angles with it on each side.
Which of the segment below is a secant?
AD
What is the coordinate of the midpoint of segment AD?
-2.5
If line segment AD equals 12 meters what is the length of line segment AB?
24
How do you draw a line segment of root 12cm?
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
How can you prove a triangle ABC is isosceles if angle BAD is congruent to angle CAD and line AD is perpendicular to line Bc?
Given: AD perpendicular to BC; angle BAD congruent to CAD Prove: ABC is isosceles Plan: Principle a.s.a Proof: 1. angle BAD congruent to angle CAD (given) 2. Since AD is perpendicular to BC, then the angle BDA is congruent to the angle CDA (all right angles are congruent). 3. AD is congruent to AD (reflexive property) 4. triangle BAD congruent to triangle CAD (principle a.s.a) 5. AB is congruent to AC (corresponding parts of congruent triangles are congruent) 6. triangle ABC is isosceles (it has two congruent sides)
If line segment ac is perpendicular to line segment cb and the measurement of angle cbd is 125 degrees then the measurement of angle a equals?
Here is the problem with this question. If AC is perpendicular to CB, then they must share a common endpoint, namely C. And we know that angle ACB must be a right angle. Now in order to make CBD 125 degrees, we need to draw it so it is greater than a right angle. So draw the line AC and at the point C, drop a perpendicular downwards and this is CB. Now D must be to the left and below B in order for the angle to be 125. Here is the catch.. We were never given any info about angle A, we only have point A. So one assumption would be to connect D and A and make segment AD. Then we have a quadralateral with two angle know, namely 125 and which is CBD and 90 which is ACB. The sum of the angles is 360 so the other two must be 360-(125+90)=145. This would be the sum of angles CAD and BDA. The length of segment BD would determine angle CAD and we do not know that So we don't have enough information. then the measurement of angle A equals:
What has four sides ad four angles?
Any quadrilateral.
When did the angles migrate to the british isles?
Around 700 AD
What were the three Germanic tribes in Britain around 450 AD through 550 AD?
Among the tribes were Angles, Saxons, Jutes, Franks, Burgundians, Visigoths, Suevi, Ostrogoths, Lombards, and Vandals.
