If the graph of the function is a continuous line then the function is differentiable.
Also if the graph suddenly make a deviation at any point then the function is not differentiable at that point .
The slope of a tangent at any point of the graph gives the derivative of the function at that point.
A zero of a function is a point at which the value of the function is zero. If you graph the function, it is a point at which the graph touches the x-axis.
This graph fails the vertical line test at x = 3This graph is not the graph of a function.
A graph represents a function if and only if every input generates a single output.
No, the graph of an oval/ellipse is not a function because it does not pass the vertical line test.
If the function is a straight line equation that passes through the graph once, then that's a function, anything on a graph is a relation!
An intuitive answer (NOTE: this is far from precise!) A function is continuous if you can trace its graph without lifting your pencil from the page. If, additionally, it is smooth everywhere without any jagged edges or abrupt corners, then it is differentiable. It is not possible for a function to be differentiable but not continuous. On the other hand, plenty of functions are continuous without being differentiable.
A differentiable function, possibly - to distinguish it from one whose graph is a kinked curve.
Definition: A function f is differentiable at a if f'(a) exists. it is differentiable on an open interval (a, b) [or (a, ∞) or (-∞, a) or (-∞, ∞)]if it is differentiable at every number in the interval.Example: Where is the function f(x) = |x| differentiable?Answer:1. f is differentiable for any x > 0 and x < 0.2. f is not differentiable at x = 0.That's mean that the curve y = |x| has not a tangent at (0, 0).Thus, both continiuty and differentiability are desirable properties for a function to have. These properties are related.Theorem: If f is differentiable at a, then f is continuous at a.The converse theorem is false, that is, there are functions that are continuous but not differentiable. (As we saw at the example above. f(x) = |x| is contionuous at 0, but is not differentiable at 0).The three ways for f not to be differentiable at aare:a) if the graph of a function f has a "corner" or a "kink" in it,b) a discontinuity,c) a vertical tangent
Weistrass function is continuous everywhere but not differentiable everywhere
If it is a differentiable function, you find the value at which its derivative is 0. But in general, you can plot it as a line graph and see where it peaks.
No.
Wherever a function is differentiable, it must also be continuous. The opposite is not true, however. For example, the absolute value function, f(x) =|x|, is not differentiable at x=0 even though it is continuous everywhere.
The signum function is differentiable with derivative 0 everywhere except at 0, where it is not differentiable in the ordinary sense. However, but under the generalised notion of differentiation in distribution theory, the derivative of the signum function is two times the Dirac delta function or twice the unit impulse function.
which function is not differentiable infinitely many time.
Both are polynomials. They are continuous and are differentiable.
A function is differentiable at a point if the derivative exists there.
A cubic function is a smooth function (differentiable everywhere). It has no vertices anywhere.